14 Both are 0-based, but the start is inclusive and the end is exclusive. This ensures the resulting string is of length start - end. To make life easier for substring operation, imagine that …

May 31, 2012 · I always thought if I do String s = "Hello World".substring(0, 5), then I just get a new string s = "Hello". This is also documented in the Java API doc: "Returns a new string that …

“Substring creates a new object out of source string by taking a portion of original string”. Until Java 1.7, substring holds the reference of the original character array, which means even a …

Apr 19, 2013 · Strings in Java are immutable. Basically this means that, once you create a string object, you won't be able to modify/change the content of a string. As a result, if you perform …

Oct 29, 2014 · The second example already shows why the choice to use an inclusive start index and an exclusive end index might be a good idea: It's easy to slice out a substring of a certain …

Feb 18, 2017 · In the example code above we use the String.substring () method to gather our sub-string from within the string. To get this sub-string we need to supply the String.substring …

12 You can use Apache commons: For substring after last occurrence use this method. And for substring after first occurrence equivalent method is here.

Do you always need first 3 characters then why not set int1 = 0 and int2 = 3? What is the problem actually in doing that? Do you expect the string to be less than 3 characters in cases. Even if …

In Java, how do I check if a string contains a substring (ignoring case)? [duplicate] Asked 15 years, 9 months ago Modified 3 years, 11 months ago Viewed 1.3m times

Hi I have to compute if a given string is substring of a bigger string. For example String str = "Hallo my world"; String substr = "my" The method "contains" should return true because str contains